Solve (-2)^2*(-4)^3-3^3*(-1)^2

$$( - 2 ) ^ { 2 } \times ( - 4 ) ^ { 3 } - 3 ^ { 3 } \times ( - 1 ) ^ { 2 }$$

Evaluate

$$-283$$

Solution Steps

Calculate -2 to the power of 2 and get 4.

$$4\left(-4\right)^{3}-3^{3}\left(-1\right)^{2}$$

Calculate -4 to the power of 3 and get -64.

$$4\left(-64\right)-3^{3}\left(-1\right)^{2}$$

Multiply 4 and -64 to get -256.

$$-256-3^{3}\left(-1\right)^{2}$$

Calculate 3 to the power of 3 and get 27.

$$-256-27\left(-1\right)^{2}$$

Calculate -1 to the power of 2 and get 1.

$$-256-27\times 1$$

Multiply 27 and 1 to get 27.

$$-256-27$$

Subtract 27 from -256 to get -283.

$$-283$$

Factor

$$-283$$