Solve (-2)^2*4^2:(-2)^6-(-3)^3

$$( - 2 ) ^ { 2 } \cdot 4 ^ { 2 } : ( - 2 ) ^ { 6 } - ( - 3 ) ^ { 3 }$$

Evaluate

$$28$$

Solution Steps

Cancel out \left(-2\right)^{2} in both numerator and denominator.

$$\frac{4^{2}}{\left(-2\right)^{4}}-\left(-3\right)^{3}$$

Calculate 4 to the power of 2 and get 16.

$$\frac{16}{\left(-2\right)^{4}}-\left(-3\right)^{3}$$

Calculate -2 to the power of 4 and get 16.

$$\frac{16}{16}-\left(-3\right)^{3}$$

Divide 16 by 16 to get 1.

$$1-\left(-3\right)^{3}$$

Calculate -3 to the power of 3 and get -27.

$$1-\left(-27\right)$$

The opposite of -27 is 27.

$$1+27$$

Add 1 and 27 to get 28.

$$28$$

Factor

$$2^{2}\times 7$$