Solve (-2)^-3=1/(-2)^3=1/-8=

$$( - 2 ) ^ { - 3 } = \frac { 1 } { ( - 2 ) ^ { 3 } } = \frac { 1 } { - 8 } =$$

Verify

Solution Steps

Calculate -2 to the power of -3 and get -\frac{1}{8}.

$$-\frac{1}{8}=\frac{1}{\left(-2\right)^{3}}\text{ and }\frac{1}{\left(-2\right)^{3}}=\frac{1}{-8}$$

Calculate -2 to the power of 3 and get -8.

$$-\frac{1}{8}=\frac{1}{-8}\text{ and }\frac{1}{\left(-2\right)^{3}}=\frac{1}{-8}$$

Fraction \frac{1}{-8} can be rewritten as -\frac{1}{8} by extracting the negative sign.

$$-\frac{1}{8}=-\frac{1}{8}\text{ and }\frac{1}{\left(-2\right)^{3}}=\frac{1}{-8}$$

Compare -\frac{1}{8} and -\frac{1}{8}.

$$\text{true}\text{ and }\frac{1}{\left(-2\right)^{3}}=\frac{1}{-8}$$

Calculate -2 to the power of 3 and get -8.

$$\text{true}\text{ and }\frac{1}{-8}=\frac{1}{-8}$$

Fraction \frac{1}{-8} can be rewritten as -\frac{1}{8} by extracting the negative sign.

$$\text{true}\text{ and }-\frac{1}{8}=\frac{1}{-8}$$

Fraction \frac{1}{-8} can be rewritten as -\frac{1}{8} by extracting the negative sign.

$$\text{true}\text{ and }-\frac{1}{8}=-\frac{1}{8}$$

Compare -\frac{1}{8} and -\frac{1}{8}.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$