Solve (-2)+(-3)*[(-4)+2]-(-3)div|-2|

$$( - 2 ) + ( - 3 ) \times [ ( - 4 ) + 2 ] - ( - 3 ) \div | - 2 |$$

Evaluate

$$\frac{11}{2}=5.5$$

Solution Steps

Add -4 and 2 to get -2.

$$-2-3\left(-2\right)-\frac{-3}{|-2|}$$

Multiply -3 and -2 to get 6.

$$-2+6-\frac{-3}{|-2|}$$

Add -2 and 6 to get 4.

$$4-\frac{-3}{|-2|}$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -2 is 2.

$$4-\frac{-3}{2}$$

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$4-\left(-\frac{3}{2}\right)$$

The opposite of -\frac{3}{2} is \frac{3}{2}.

$$4+\frac{3}{2}$$

Convert 4 to fraction \frac{8}{2}.

$$\frac{8}{2}+\frac{3}{2}$$

Since \frac{8}{2} and \frac{3}{2} have the same denominator, add them by adding their numerators.

$$\frac{8+3}{2}$$

Add 8 and 3 to get 11.

$$\frac{11}{2}$$

Factor

$$\frac{11}{2} = 5\frac{1}{2} = 5.5$$