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-2\left(\sqrt{3}\right)^{2}+10\sqrt{3}+2\sqrt{3}-10
Apply the distributive property by multiplying each term of -2\sqrt{3}+2 by each term of \sqrt{3}-5.
-2\times 3+10\sqrt{3}+2\sqrt{3}-10
The square of \sqrt{3} is 3.
-6+10\sqrt{3}+2\sqrt{3}-10
Multiply -2 and 3 to get -6.
-6+12\sqrt{3}-10
Combine 10\sqrt{3} and 2\sqrt{3} to get 12\sqrt{3}.
-16+12\sqrt{3}
Subtract 10 from -6 to get -16.