Solve (-2*10(-1/2*2^2)+1/2^2

$$( - 2 \cdot 10 ( - \frac { 1 } { 2 } \cdot 2 ^ { 2 } ) + \frac { 1 } { 2 ^ { 2 } }$$

Evaluate

$$\frac{161}{4}=40.25$$

Solution Steps

Multiply -2 and 10 to get -20.

$$-20\left(-\frac{1}{2}\right)\times 2^{2}+\frac{1}{2^{2}}$$

Express -20\left(-\frac{1}{2}\right) as a single fraction.

$$\frac{-20\left(-1\right)}{2}\times 2^{2}+\frac{1}{2^{2}}$$

Multiply -20 and -1 to get 20.

$$\frac{20}{2}\times 2^{2}+\frac{1}{2^{2}}$$

Divide 20 by 2 to get 10.

$$10\times 2^{2}+\frac{1}{2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$10\times 4+\frac{1}{2^{2}}$$

Multiply 10 and 4 to get 40.

$$40+\frac{1}{2^{2}}$$

Calculate 2 to the power of 2 and get 4.

$$40+\frac{1}{4}$$

Convert 40 to fraction \frac{160}{4}.

$$\frac{160}{4}+\frac{1}{4}$$

Since \frac{160}{4} and \frac{1}{4} have the same denominator, add them by adding their numerators.

$$\frac{160+1}{4}$$

Add 160 and 1 to get 161.

$$\frac{161}{4}$$

Factor

$$\frac{7 \cdot 23}{2 ^ {2}} = 40\frac{1}{4} = 40.25$$