Solve (-2^{2})^{3}:(+2)^{4}-(-5)^3*(+5)^5:(-5)^6-(-20)^2:(-25)=

$$( - 2 ^ { 2 } ) ^ { 3 } : ( + 2 ) ^ { 4 } - ( - 5 ) ^ { 3 } \cdot ( + 5 ) ^ { 5 } : ( - 5 ) ^ { 6 } - ( - 20 ) ^ { 2 } : ( - 25 ) =$$

Evaluate

$$37$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$\frac{\left(-4\right)^{3}}{2^{4}}-\frac{\left(-5\right)^{3}\times 5^{5}}{\left(-5\right)^{6}}-\frac{\left(-20\right)^{2}}{-25}$$

Calculate -4 to the power of 3 and get -64.

$$\frac{-64}{2^{4}}-\frac{\left(-5\right)^{3}\times 5^{5}}{\left(-5\right)^{6}}-\frac{\left(-20\right)^{2}}{-25}$$

Calculate 2 to the power of 4 and get 16.

$$\frac{-64}{16}-\frac{\left(-5\right)^{3}\times 5^{5}}{\left(-5\right)^{6}}-\frac{\left(-20\right)^{2}}{-25}$$

Divide -64 by 16 to get -4.

$$-4-\frac{\left(-5\right)^{3}\times 5^{5}}{\left(-5\right)^{6}}-\frac{\left(-20\right)^{2}}{-25}$$

Cancel out \left(-5\right)^{3} in both numerator and denominator.

$$-4-\frac{5^{5}}{\left(-5\right)^{3}}-\frac{\left(-20\right)^{2}}{-25}$$

Calculate 5 to the power of 5 and get 3125.

$$-4-\frac{3125}{\left(-5\right)^{3}}-\frac{\left(-20\right)^{2}}{-25}$$

Calculate -5 to the power of 3 and get -125.

$$-4-\frac{3125}{-125}-\frac{\left(-20\right)^{2}}{-25}$$

Divide 3125 by -125 to get -25.

$$-4-\left(-25\right)-\frac{\left(-20\right)^{2}}{-25}$$

The opposite of -25 is 25.

$$-4+25-\frac{\left(-20\right)^{2}}{-25}$$

Add -4 and 25 to get 21.

$$21-\frac{\left(-20\right)^{2}}{-25}$$

Calculate -20 to the power of 2 and get 400.

$$21-\frac{400}{-25}$$

Divide 400 by -25 to get -16.

$$21-\left(-16\right)$$

The opposite of -16 is 16.

$$21+16$$

Add 21 and 16 to get 37.

$$37$$

Factor

$$37$$