Solve (-10)^2+[(-4)^2-(3+3^2)*2]

$$( - 10 ) ^ { 2 } + [ ( - 4 ) ^ { 2 } - ( 3 + 3 ^ { 2 } ) \times 2 ]$$

Evaluate

$$92$$

Solution Steps

Calculate -10 to the power of 2 and get 100.

$$100+\left(-4\right)^{2}-\left(3+3^{2}\right)\times 2$$

Calculate -4 to the power of 2 and get 16.

$$100+16-\left(3+3^{2}\right)\times 2$$

Calculate 3 to the power of 2 and get 9.

$$100+16-\left(3+9\right)\times 2$$

Add 3 and 9 to get 12.

$$100+16-12\times 2$$

Multiply 12 and 2 to get 24.

$$100+16-24$$

Subtract 24 from 16 to get -8.

$$100-8$$

Subtract 8 from 100 to get 92.

$$92$$

Factor

$$2^{2}\times 23$$