Solve (-10)^-2*(-10)^0+10^-2*10^0

$$( - 10 ) ^ { - 2 } \times ( - 10 ) ^ { 0 } + 10 ^ { - 2 } \times 10 ^ { 0 }$$

Evaluate

$$\frac{1}{50}=0.02$$

Solution Steps

To multiply powers of the same base, add their exponents. Add -2 and 0 to get -2.

$$\left(-10\right)^{-2}+10^{-2}\times 10^{0}$$

To multiply powers of the same base, add their exponents. Add -2 and 0 to get -2.

$$\left(-10\right)^{-2}+10^{-2}$$

Calculate -10 to the power of -2 and get \frac{1}{100}.

$$\frac{1}{100}+10^{-2}$$

Calculate 10 to the power of -2 and get \frac{1}{100}.

$$\frac{1}{100}+\frac{1}{100}$$

Add \frac{1}{100} and \frac{1}{100} to get \frac{1}{50}.

$$\frac{1}{50}$$

Factor

$$\frac{1}{2 \cdot 5 ^ {2}} = 0.02$$