Solve (-10)[1-4^2+(-2)^5]+7-20+40

$$( - 10 ) [ 1 - 4 ^ { 2 } + ( - 2 ) ^ { 5 } ] + 7 - 20 + 40$$

Evaluate

$$497$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$-10\left(1-16+\left(-2\right)^{5}\right)+7-20+40$$

Subtract 16 from 1 to get -15.

$$-10\left(-15+\left(-2\right)^{5}\right)+7-20+40$$

Calculate -2 to the power of 5 and get -32.

$$-10\left(-15-32\right)+7-20+40$$

Subtract 32 from -15 to get -47.

$$-10\left(-47\right)+7-20+40$$

Multiply -10 and -47 to get 470.

$$470+7-20+40$$

Add 470 and 7 to get 477.

$$477-20+40$$

Subtract 20 from 477 to get 457.

$$457+40$$

Add 457 and 40 to get 497.

$$497$$

Factor

$$7\times 71$$