Solve (-1)^4-(1-05)*1/3*[2-(-2)^2]

$$( - 1 ) ^ { 4 } - ( 1 - 05 ) \times \frac { 1 } { 3 } \times [ 2 - ( - 2 ) ^ { 2 } ]$$

Evaluate

$$\frac{5}{3}\approx 1.666666667$$

Solution Steps

Calculate -1 to the power of 4 and get 1.

$$1-\left(1-0\times 5\right)\times \frac{1}{3}\left(2-\left(-2\right)^{2}\right)$$

Multiply 0 and 5 to get 0.

$$1-\left(1-0\right)\times \frac{1}{3}\left(2-\left(-2\right)^{2}\right)$$

Subtract 0 from 1 to get 1.

$$1-1\times \frac{1}{3}\left(2-\left(-2\right)^{2}\right)$$

Multiply 1 and \frac{1}{3} to get \frac{1}{3}.

$$1-\frac{1}{3}\left(2-\left(-2\right)^{2}\right)$$

Calculate -2 to the power of 2 and get 4.

$$1-\frac{1}{3}\left(2-4\right)$$

Subtract 4 from 2 to get -2.

$$1-\frac{1}{3}\left(-2\right)$$

Multiply \frac{1}{3} and -2 to get \frac{-2}{3}.

$$1-\frac{-2}{3}$$

Fraction \frac{-2}{3} can be rewritten as -\frac{2}{3} by extracting the negative sign.

$$1-\left(-\frac{2}{3}\right)$$

The opposite of -\frac{2}{3} is \frac{2}{3}.

$$1+\frac{2}{3}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{3}{3}+\frac{2}{3}$$

Since \frac{3}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{3+2}{3}$$

Add 3 and 2 to get 5.

$$\frac{5}{3}$$

Factor

$$\frac{5}{3} = 1\frac{2}{3} = 1.6666666666666667$$