Solve (-1)^4-(1-0.5)*1/3*[2-(-2)^2]

$$( - 1 ) ^ { 4 } - ( 1 - 0.5 ) \times \frac { 1 } { 3 } \times [ 2 - ( - 2 ) ^ { 2 } ]$$

Evaluate

$$\frac{4}{3}\approx 1.333333333$$

Solution Steps

Calculate -1 to the power of 4 and get 1.

$$1-\left(1-0.5\right)\times \frac{1}{3}\left(2-\left(-2\right)^{2}\right)$$

Subtract 0.5 from 1 to get 0.5.

$$1-0.5\times \frac{1}{3}\left(2-\left(-2\right)^{2}\right)$$

Convert decimal number 0.5 to fraction \frac{5}{10}. Reduce the fraction \frac{5}{10} to lowest terms by extracting and canceling out 5.

$$1-\frac{1}{2}\times \frac{1}{3}\left(2-\left(-2\right)^{2}\right)$$

Multiply \frac{1}{2} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$1-\frac{1\times 1}{2\times 3}\left(2-\left(-2\right)^{2}\right)$$

Do the multiplications in the fraction \frac{1\times 1}{2\times 3}.

$$1-\frac{1}{6}\left(2-\left(-2\right)^{2}\right)$$

Calculate -2 to the power of 2 and get 4.

$$1-\frac{1}{6}\left(2-4\right)$$

Subtract 4 from 2 to get -2.

$$1-\frac{1}{6}\left(-2\right)$$

Multiply \frac{1}{6} and -2 to get \frac{-2}{6}.

$$1-\frac{-2}{6}$$

Reduce the fraction \frac{-2}{6} to lowest terms by extracting and canceling out 2.

$$1-\left(-\frac{1}{3}\right)$$

The opposite of -\frac{1}{3} is \frac{1}{3}.

$$1+\frac{1}{3}$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{3}{3}+\frac{1}{3}$$

Since \frac{3}{3} and \frac{1}{3} have the same denominator, add them by adding their numerators.

$$\frac{3+1}{3}$$

Add 3 and 1 to get 4.

$$\frac{4}{3}$$

Factor

$$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$$