Solve (-1)^3-1/4*[2-(-3)^2]

$$( - 1 ) ^ { 3 } - \frac { 1 } { 4 } \times [ 2 - ( - 3 ) ^ { 2 } ]$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Calculate -1 to the power of 3 and get -1.

$$-1-\frac{1}{4}\left(2-\left(-3\right)^{2}\right)$$

Calculate -3 to the power of 2 and get 9.

$$-1-\frac{1}{4}\left(2-9\right)$$

Subtract 9 from 2 to get -7.

$$-1-\frac{1}{4}\left(-7\right)$$

Multiply \frac{1}{4} and -7 to get \frac{-7}{4}.

$$-1-\frac{-7}{4}$$

Fraction \frac{-7}{4} can be rewritten as -\frac{7}{4} by extracting the negative sign.

$$-1-\left(-\frac{7}{4}\right)$$

The opposite of -\frac{7}{4} is \frac{7}{4}.

$$-1+\frac{7}{4}$$

Convert -1 to fraction -\frac{4}{4}.

$$-\frac{4}{4}+\frac{7}{4}$$

Since -\frac{4}{4} and \frac{7}{4} have the same denominator, add them by adding their numerators.

$$\frac{-4+7}{4}$$

Add -4 and 7 to get 3.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$