Solve (-1)^3+(7-2-1)^4+sqrt{64}-1/2+4

$$( - 1 ) ^ { 3 } + ( 7 - 2 - 1 ) ^ { 4 } + \sqrt { 64 } - \frac { 1 } { 2 } + 4$$

Evaluate

$$\frac{533}{2}=266.5$$

Solution Steps

Calculate -1 to the power of 3 and get -1.

$$-1+\left(7-2-1\right)^{4}+\sqrt{64}-\frac{1}{2}+4$$

Subtract 2 from 7 to get 5.

$$-1+\left(5-1\right)^{4}+\sqrt{64}-\frac{1}{2}+4$$

Subtract 1 from 5 to get 4.

$$-1+4^{4}+\sqrt{64}-\frac{1}{2}+4$$

Calculate 4 to the power of 4 and get 256.

$$-1+256+\sqrt{64}-\frac{1}{2}+4$$

Add -1 and 256 to get 255.

$$255+\sqrt{64}-\frac{1}{2}+4$$

Calculate the square root of 64 and get 8.

$$255+8-\frac{1}{2}+4$$

Add 255 and 8 to get 263.

$$263-\frac{1}{2}+4$$

Subtract \frac{1}{2} from 263 to get \frac{525}{2}.

$$\frac{525}{2}+4$$

Add \frac{525}{2} and 4 to get \frac{533}{2}.

$$\frac{533}{2}$$

Factor

$$\frac{13 \cdot 41}{2} = 266\frac{1}{2} = 266.5$$