Solve (-1)^2009+(-1/2)^-2-(pi-1)^0-|-3|

$$( - 1 ) ^ { 2009 } + ( - \frac { 1 } { 2 } ) ^ { - 2 } - ( \pi - 1 ) ^ { 0 } - | - 3 |$$

Evaluate

$$-1$$

Solution Steps

Calculate -1 to the power of 2009 and get -1.

$$-1+\left(-\frac{1}{2}\right)^{-2}-\left(\pi -1\right)^{0}-|-3|$$

Calculate -\frac{1}{2} to the power of -2 and get 4.

$$-1+4-\left(\pi -1\right)^{0}-|-3|$$

Add -1 and 4 to get 3.

$$3-\left(\pi -1\right)^{0}-|-3|$$

Calculate \pi -1 to the power of 0 and get 1.

$$3-1-|-3|$$

Subtract 1 from 3 to get 2.

$$2-|-3|$$

The absolute value of a real number a is a when a\geq 0, or -a when a<0. The absolute value of -3 is 3.

$$2-3$$

Subtract 3 from 2 to get -1.

$$-1$$

Factor

$$-1$$