Solve (-1)^2-12-6*3+(-3)*(-2)+22-(-3)*2

$$( - 1 ) ^ { 2 } - 12 - 6 \cdot 3 + ( - 3 ) \cdot ( - 2 ) + 22 - ( - 3 ) \cdot 2$$

Evaluate

$$5$$

Solution Steps

Calculate -1 to the power of 2 and get 1.

$$1-12-6\times 3-3\left(-2\right)+22-\left(-3\times 2\right)$$

Subtract 12 from 1 to get -11.

$$-11-6\times 3-3\left(-2\right)+22-\left(-3\times 2\right)$$

Multiply 6 and 3 to get 18.

$$-11-18-3\left(-2\right)+22-\left(-3\times 2\right)$$

Subtract 18 from -11 to get -29.

$$-29-3\left(-2\right)+22-\left(-3\times 2\right)$$

Multiply -3 and -2 to get 6.

$$-29+6+22-\left(-3\times 2\right)$$

Add -29 and 6 to get -23.

$$-23+22-\left(-3\times 2\right)$$

Add -23 and 22 to get -1.

$$-1-\left(-3\times 2\right)$$

Multiply -3 and 2 to get -6.

$$-1-\left(-6\right)$$

The opposite of -6 is 6.

$$-1+6$$

Add -1 and 6 to get 5.

$$5$$

Factor

$$5$$