Solve (-12/3)^3*(-0.75)^2*(-0.024)=

$$( - 1 \frac { 2 } { 3 } ) ^ { 3 } \cdot ( - 0.75 ) ^ { 2 } \cdot ( - 0.024 ) =$$

Evaluate

$$0.0625$$

Solution Steps

Multiply 1 and 3 to get 3.

$$\left(-\frac{3+2}{3}\right)^{3}\left(-0.75\right)^{2}\left(-0.024\right)$$

Add 3 and 2 to get 5.

$$\left(-\frac{5}{3}\right)^{3}\left(-0.75\right)^{2}\left(-0.024\right)$$

Calculate -\frac{5}{3} to the power of 3 and get -\frac{125}{27}.

$$-\frac{125}{27}\left(-0.75\right)^{2}\left(-0.024\right)$$

Calculate -0.75 to the power of 2 and get 0.5625.

$$-\frac{125}{27}\times 0.5625\left(-0.024\right)$$

Multiply -\frac{125}{27} and 0.5625 to get -\frac{125}{48}.

$$-\frac{125}{48}\left(-0.024\right)$$

Multiply -\frac{125}{48} and -0.024 to get \frac{1}{16}.

$$\frac{1}{16}$$

Factor

$$\frac{1}{2 ^ {4}} = 0.0625$$