Solve (-11/6)*(-33/8)*(-2019)*(-1/2+0.5)

$$( - 1 \frac { 1 } { 6 } ) \times ( - 3 \frac { 3 } { 8 } ) \times ( - 2019 ) \times ( - \frac { 1 } { 2 } + 0.5 )$$

Evaluate

$$0$$

Solution Steps

Multiply 1 and 6 to get 6.

$$\left(-\frac{6+1}{6}\right)\left(-\frac{3\times 8+3}{8}\right)\left(-2019\right)\left(-\frac{1}{2}+0.5\right)$$

Add 6 and 1 to get 7.

$$-\frac{7}{6}\left(-\frac{3\times 8+3}{8}\right)\left(-2019\right)\left(-\frac{1}{2}+0.5\right)$$

Multiply 3 and 8 to get 24.

$$-\frac{7}{6}\left(-\frac{24+3}{8}\right)\left(-2019\right)\left(-\frac{1}{2}+0.5\right)$$

Add 24 and 3 to get 27.

$$-\frac{7}{6}\left(-\frac{27}{8}\right)\left(-2019\right)\left(-\frac{1}{2}+0.5\right)$$

Multiply -\frac{7}{6} times -\frac{27}{8} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-7\left(-27\right)}{6\times 8}\left(-2019\right)\left(-\frac{1}{2}+0.5\right)$$

Do the multiplications in the fraction \frac{-7\left(-27\right)}{6\times 8}.

$$\frac{189}{48}\left(-2019\right)\left(-\frac{1}{2}+0.5\right)$$

Reduce the fraction \frac{189}{48} to lowest terms by extracting and canceling out 3.

$$\frac{63}{16}\left(-2019\right)\left(-\frac{1}{2}+0.5\right)$$

Express \frac{63}{16}\left(-2019\right) as a single fraction.

$$\frac{63\left(-2019\right)}{16}\left(-\frac{1}{2}+0.5\right)$$

Multiply 63 and -2019 to get -127197.

$$\frac{-127197}{16}\left(-\frac{1}{2}+0.5\right)$$

Fraction \frac{-127197}{16} can be rewritten as -\frac{127197}{16} by extracting the negative sign.

$$-\frac{127197}{16}\left(-\frac{1}{2}+0.5\right)$$

Add -\frac{1}{2} and 0.5 to get 0.

$$-\frac{127197}{16}\times 0$$

Multiply -\frac{127197}{16} and 0 to get 0.

$$0$$

Factor

$$0$$