Solve (-11/6+31/3)*450=

$$( - 1 \frac { 1 } { 6 } + 3 \frac { 1 } { 3 } ) \cdot 450 =$$

Evaluate

$$975$$

Solution Steps

Multiply 1 and 6 to get 6.

$$\left(-\frac{6+1}{6}+\frac{3\times 3+1}{3}\right)\times 450$$

Add 6 and 1 to get 7.

$$\left(-\frac{7}{6}+\frac{3\times 3+1}{3}\right)\times 450$$

Multiply 3 and 3 to get 9.

$$\left(-\frac{7}{6}+\frac{9+1}{3}\right)\times 450$$

Add 9 and 1 to get 10.

$$\left(-\frac{7}{6}+\frac{10}{3}\right)\times 450$$

Least common multiple of 6 and 3 is 6. Convert -\frac{7}{6} and \frac{10}{3} to fractions with denominator 6.

$$\left(-\frac{7}{6}+\frac{20}{6}\right)\times 450$$

Since -\frac{7}{6} and \frac{20}{6} have the same denominator, add them by adding their numerators.

$$\frac{-7+20}{6}\times 450$$

Add -7 and 20 to get 13.

$$\frac{13}{6}\times 450$$

Express \frac{13}{6}\times 450 as a single fraction.

$$\frac{13\times 450}{6}$$

Multiply 13 and 450 to get 5850.

$$\frac{5850}{6}$$

Divide 5850 by 6 to get 975.

$$975$$

Factor

$$3\times 5^{2}\times 13$$