Solve (-11/3)+(-21/6)

$$( - 1 \frac { 1 } { 3 } ) + ( - 2 \frac { 1 } { 6 } )$$

Evaluate

$$-\frac{7}{2}=-3.5$$

Solution Steps

Multiply 1 and 3 to get 3.

$$-\frac{3+1}{3}-\frac{2\times 6+1}{6}$$

Add 3 and 1 to get 4.

$$-\frac{4}{3}-\frac{2\times 6+1}{6}$$

Multiply 2 and 6 to get 12.

$$-\frac{4}{3}-\frac{12+1}{6}$$

Add 12 and 1 to get 13.

$$-\frac{4}{3}-\frac{13}{6}$$

Least common multiple of 3 and 6 is 6. Convert -\frac{4}{3} and \frac{13}{6} to fractions with denominator 6.

$$-\frac{8}{6}-\frac{13}{6}$$

Since -\frac{8}{6} and \frac{13}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-8-13}{6}$$

Subtract 13 from -8 to get -21.

$$\frac{-21}{6}$$

Reduce the fraction \frac{-21}{6} to lowest terms by extracting and canceling out 3.

$$-\frac{7}{2}$$

Factor

$$-\frac{7}{2} = -3\frac{1}{2} = -3.5$$