Solve (-11/2)*(-21/3)*(-31/4)*24

$$( - 1 \frac { 1 } { 2 } ) \times ( - 2 \frac { 1 } { 3 } ) \times ( - 3 \frac { 1 } { 4 } ) \times 24$$

Evaluate

$$-273$$

Solution Steps

Multiply 1 and 2 to get 2.

$$\left(-\frac{2+1}{2}\right)\left(-\frac{2\times 3+1}{3}\right)\left(-\frac{3\times 4+1}{4}\right)\times 24$$

Add 2 and 1 to get 3.

$$-\frac{3}{2}\left(-\frac{2\times 3+1}{3}\right)\left(-\frac{3\times 4+1}{4}\right)\times 24$$

Multiply 2 and 3 to get 6.

$$-\frac{3}{2}\left(-\frac{6+1}{3}\right)\left(-\frac{3\times 4+1}{4}\right)\times 24$$

Add 6 and 1 to get 7.

$$-\frac{3}{2}\left(-\frac{7}{3}\right)\left(-\frac{3\times 4+1}{4}\right)\times 24$$

Multiply -\frac{3}{2} times -\frac{7}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3\left(-7\right)}{2\times 3}\left(-\frac{3\times 4+1}{4}\right)\times 24$$

Do the multiplications in the fraction \frac{-3\left(-7\right)}{2\times 3}.

$$\frac{21}{6}\left(-\frac{3\times 4+1}{4}\right)\times 24$$

Reduce the fraction \frac{21}{6} to lowest terms by extracting and canceling out 3.

$$\frac{7}{2}\left(-\frac{3\times 4+1}{4}\right)\times 24$$

Multiply 3 and 4 to get 12.

$$\frac{7}{2}\left(-\frac{12+1}{4}\right)\times 24$$

Add 12 and 1 to get 13.

$$\frac{7}{2}\left(-\frac{13}{4}\right)\times 24$$

Multiply \frac{7}{2} times -\frac{13}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\left(-13\right)}{2\times 4}\times 24$$

Do the multiplications in the fraction \frac{7\left(-13\right)}{2\times 4}.

$$\frac{-91}{8}\times 24$$

Fraction \frac{-91}{8} can be rewritten as -\frac{91}{8} by extracting the negative sign.

$$-\frac{91}{8}\times 24$$

Express -\frac{91}{8}\times 24 as a single fraction.

$$\frac{-91\times 24}{8}$$

Multiply -91 and 24 to get -2184.

$$\frac{-2184}{8}$$

Divide -2184 by 8 to get -273.

$$-273$$

Factor

$$-273$$