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1-2\sqrt{3}+\left(\sqrt{3}\right)^{2}-\sqrt{3}
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(-1+\sqrt{3}\right)^{2}.
1-2\sqrt{3}+3-\sqrt{3}
The square of \sqrt{3} is 3.
4-2\sqrt{3}-\sqrt{3}
Add 1 and 3 to get 4.
4-3\sqrt{3}
Combine -2\sqrt{3} and -\sqrt{3} to get -3\sqrt{3}.