Solve (-0.7)^2*10^2+(-0.2*10)^3

$$( - 0.7 ) ^ { 2 } \cdot 10 ^ { 2 } + ( - 0.2 \cdot 10 ) ^ { 3 }$$

Evaluate

$$41$$

Solution Steps

Calculate -0.7 to the power of 2 and get 0.49.

$$0.49\times 10^{2}+\left(-0.2\times 10\right)^{3}$$

Calculate 10 to the power of 2 and get 100.

$$0.49\times 100+\left(-0.2\times 10\right)^{3}$$

Multiply 0.49 and 100 to get 49.

$$49+\left(-0.2\times 10\right)^{3}$$

Multiply -0.2 and 10 to get -2.

$$49+\left(-2\right)^{3}$$

Calculate -2 to the power of 3 and get -8.

$$49-8$$

Subtract 8 from 49 to get 41.

$$41$$

Factor

$$41$$