Solve (-0div2)-3(-6*3)+(-4)(-9+10)+(2-3)

$$( - 0 \div 2 ) - 3 ( - 6 \times 3 ) + ( - 4 ) ( - 9 + 10 ) + ( 2 - 3 )$$

Evaluate

$$49$$

Solution Steps

Zero divided by any non-zero number gives zero.

$$0-3\left(-6\right)\times 3-4\left(-9+10\right)+2-3$$

Multiply 3 and -6 to get -18.

$$0-\left(-18\times 3\right)-4\left(-9+10\right)+2-3$$

Multiply -18 and 3 to get -54.

$$0-\left(-54\right)-4\left(-9+10\right)+2-3$$

The opposite of -54 is 54.

$$0+54-4\left(-9+10\right)+2-3$$

Add 0 and 54 to get 54.

$$54-4\left(-9+10\right)+2-3$$

Add -9 and 10 to get 1.

$$54-4+2-3$$

Subtract 4 from 54 to get 50.

$$50+2-3$$

Add 50 and 2 to get 52.

$$52-3$$

Subtract 3 from 52 to get 49.

$$49$$

Factor

$$7^{2}$$