Solve (-sqrt{6})^2-sqrt{25}+sqrt{(-3)^2}

$$( - \sqrt { 6 } ) ^ { 2 } - \sqrt { 25 } + \sqrt { ( - 3 ) ^ { 2 } }$$

Evaluate

$$4$$

Solution Steps

Calculate -\sqrt{6} to the power of 2 and get \left(\sqrt{6}\right)^{2}.

$$\left(\sqrt{6}\right)^{2}-\sqrt{25}+\sqrt{\left(-3\right)^{2}}$$

Calculate the square root of 25 and get 5.

$$\left(\sqrt{6}\right)^{2}-5+\sqrt{\left(-3\right)^{2}}$$

Calculate -3 to the power of 2 and get 9.

$$\left(\sqrt{6}\right)^{2}-5+\sqrt{9}$$

Calculate the square root of 9 and get 3.

$$\left(\sqrt{6}\right)^{2}-5+3$$

Add -5 and 3 to get -2.

$$\left(\sqrt{6}\right)^{2}-2$$

The square of \sqrt{6} is 6.

$$6-2$$

Subtract 2 from 6 to get 4.

$$4$$

Factor

$$2^{2}$$