Solve (-8/9-2/3)*(4+2/10)

$$( - \frac { 8 } { 9 } - \frac { 2 } { 3 } ) \cdot ( 4 + \frac { 2 } { 10 } )$$

Evaluate

$$-\frac{98}{15}\approx -6.533333333$$

Solution Steps

Least common multiple of 9 and 3 is 9. Convert -\frac{8}{9} and \frac{2}{3} to fractions with denominator 9.

$$\left(-\frac{8}{9}-\frac{6}{9}\right)\left(4+\frac{2}{10}\right)$$

Since -\frac{8}{9} and \frac{6}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-8-6}{9}\left(4+\frac{2}{10}\right)$$

Subtract 6 from -8 to get -14.

$$-\frac{14}{9}\left(4+\frac{2}{10}\right)$$

Reduce the fraction \frac{2}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{14}{9}\left(4+\frac{1}{5}\right)$$

Convert 4 to fraction \frac{20}{5}.

$$-\frac{14}{9}\left(\frac{20}{5}+\frac{1}{5}\right)$$

Since \frac{20}{5} and \frac{1}{5} have the same denominator, add them by adding their numerators.

$$-\frac{14}{9}\times \frac{20+1}{5}$$

Add 20 and 1 to get 21.

$$-\frac{14}{9}\times \frac{21}{5}$$

Multiply -\frac{14}{9} times \frac{21}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-14\times 21}{9\times 5}$$

Do the multiplications in the fraction \frac{-14\times 21}{9\times 5}.

$$\frac{-294}{45}$$

Reduce the fraction \frac{-294}{45} to lowest terms by extracting and canceling out 3.

$$-\frac{98}{15}$$

Factor

$$-\frac{98}{15} = -6\frac{8}{15} = -6.533333333333333$$