Solve (-7/10)*(-2)+(-7/10)*(-3)=

$$( - \frac { 7 } { 10 } ) \cdot ( - 2 ) + ( - \frac { 7 } { 10 } ) \cdot ( - 3 ) =$$

Evaluate

$$\frac{7}{2}=3.5$$

Solution Steps

Express -\frac{7}{10}\left(-2\right) as a single fraction.

$$\frac{-7\left(-2\right)}{10}-\frac{7}{10}\left(-3\right)$$

Multiply -7 and -2 to get 14.

$$\frac{14}{10}-\frac{7}{10}\left(-3\right)$$

Reduce the fraction \frac{14}{10} to lowest terms by extracting and canceling out 2.

$$\frac{7}{5}-\frac{7}{10}\left(-3\right)$$

Express -\frac{7}{10}\left(-3\right) as a single fraction.

$$\frac{7}{5}+\frac{-7\left(-3\right)}{10}$$

Multiply -7 and -3 to get 21.

$$\frac{7}{5}+\frac{21}{10}$$

Least common multiple of 5 and 10 is 10. Convert \frac{7}{5} and \frac{21}{10} to fractions with denominator 10.

$$\frac{14}{10}+\frac{21}{10}$$

Since \frac{14}{10} and \frac{21}{10} have the same denominator, add them by adding their numerators.

$$\frac{14+21}{10}$$

Add 14 and 21 to get 35.

$$\frac{35}{10}$$

Reduce the fraction \frac{35}{10} to lowest terms by extracting and canceling out 5.

$$\frac{7}{2}$$

Factor

$$\frac{7}{2} = 3\frac{1}{2} = 3.5$$