Solve (-542*10^3/2303*0.8821)*4.2

$$( - \frac { 542 \times 10 ^ { 3 } } { 2303 \times 0.8821 } ) \times 4.2$$

Evaluate

$$-\frac{3252000000}{2902109}\approx -1120.564389553$$

Solution Steps

Calculate 10 to the power of 3 and get 1000.

$$\left(-\frac{542\times 1000}{2303\times 0.8821}\right)\times 4.2$$

Multiply 542 and 1000 to get 542000.

$$\left(-\frac{542000}{2303\times 0.8821}\right)\times 4.2$$

Multiply 2303 and 0.8821 to get 2031.4763.

$$\left(-\frac{542000}{2031.4763}\right)\times 4.2$$

Expand \frac{542000}{2031.4763} by multiplying both numerator and the denominator by 10000.

$$-\frac{5420000000}{20314763}\times 4.2$$

Convert decimal number 4.2 to fraction \frac{42}{10}. Reduce the fraction \frac{42}{10} to lowest terms by extracting and canceling out 2.

$$-\frac{5420000000}{20314763}\times \frac{21}{5}$$

Multiply -\frac{5420000000}{20314763} times \frac{21}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-5420000000\times 21}{20314763\times 5}$$

Do the multiplications in the fraction \frac{-5420000000\times 21}{20314763\times 5}.

$$\frac{-113820000000}{101573815}$$

Reduce the fraction \frac{-113820000000}{101573815} to lowest terms by extracting and canceling out 35.

$$-\frac{3252000000}{2902109}$$

Factor

$$-\frac{3252000000}{2902109} = -1120\frac{1637920}{2902109} = -1120.5643895525634$$