Solve (-3b/7+b/2)*(-3)

$$( - \frac { 3 b } { 7 } + \frac { b } { 2 } ) \cdot ( - 3 )$$

Evaluate

$$-\frac{3b}{14}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 7 and 2 is 14. Multiply -\frac{3b}{7} times \frac{2}{2}. Multiply \frac{b}{2} times \frac{7}{7}.

$$\left(-\frac{2\times 3b}{14}+\frac{7b}{14}\right)\left(-3\right)$$

Since -\frac{2\times 3b}{14} and \frac{7b}{14} have the same denominator, add them by adding their numerators.

$$\frac{-2\times 3b+7b}{14}\left(-3\right)$$

Do the multiplications in -2\times 3b+7b.

$$\frac{-6b+7b}{14}\left(-3\right)$$

Combine like terms in -6b+7b.

$$\frac{b}{14}\left(-3\right)$$

Express \frac{b}{14}\left(-3\right) as a single fraction.

$$\frac{-b\times 3}{14}$$

Multiply -1 and 3 to get -3.

$$\frac{-3b}{14}$$

Expand

$$-\frac{3b}{14}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 7 and 2 is 14. Multiply -\frac{3b}{7} times \frac{2}{2}. Multiply \frac{b}{2} times \frac{7}{7}.

$$\left(-\frac{2\times 3b}{14}+\frac{7b}{14}\right)\left(-3\right)$$

Since -\frac{2\times 3b}{14} and \frac{7b}{14} have the same denominator, add them by adding their numerators.

$$\frac{-2\times 3b+7b}{14}\left(-3\right)$$

Do the multiplications in -2\times 3b+7b.

$$\frac{-6b+7b}{14}\left(-3\right)$$

Combine like terms in -6b+7b.

$$\frac{b}{14}\left(-3\right)$$

Express \frac{b}{14}\left(-3\right) as a single fraction.

$$\frac{-b\times 3}{14}$$

Multiply -1 and 3 to get -3.

$$\frac{-3b}{14}$$