Solve (-3/9)^2-4^2=8

$$( - \frac { 3 } { 9 } ) ^ { 2 } - 4 ^ { 2 } = 8$$

Verify

Solution Steps

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$\left(-\frac{1}{3}\right)^{2}-4^{2}=8$$

Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{1}{9}-4^{2}=8$$

Calculate 4 to the power of 2 and get 16.

$$\frac{1}{9}-16=8$$

Subtract 16 from \frac{1}{9} to get -\frac{143}{9}.

$$-\frac{143}{9}=8$$

Convert 8 to fraction \frac{72}{9}.

$$-\frac{143}{9}=\frac{72}{9}$$

Compare -\frac{143}{9} and \frac{72}{9}.

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