Solve (-3/8)*(2/3)*(-3/4)

$$( - \frac { 3 } { 8 } ) \times ( \frac { 2 } { 3 } ) \times ( - \frac { 3 } { 4 } )$$

Evaluate

$$\frac{3}{16}=0.1875$$

Solution Steps

Multiply -\frac{3}{8} times \frac{2}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-3\times 2}{8\times 3}\left(-\frac{3}{4}\right)$$

Do the multiplications in the fraction \frac{-3\times 2}{8\times 3}.

$$\frac{-6}{24}\left(-\frac{3}{4}\right)$$

Reduce the fraction \frac{-6}{24} to lowest terms by extracting and canceling out 6.

$$-\frac{1}{4}\left(-\frac{3}{4}\right)$$

Multiply -\frac{1}{4} times -\frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-\left(-3\right)}{4\times 4}$$

Do the multiplications in the fraction \frac{-\left(-3\right)}{4\times 4}.

$$\frac{3}{16}$$

Factor

$$\frac{3}{2 ^ {4}} = 0.1875$$