Solve (-3/4)^2+3/4-3

$$( - \frac { 3 } { 4 } ) ^ { 2 } + \frac { 3 } { 4 } - 3$$

Evaluate

$$-\frac{27}{16}=-1.6875$$

Solution Steps

Calculate -\frac{3}{4} to the power of 2 and get \frac{9}{16}.

$$\frac{9}{16}+\frac{3}{4}-3$$

Least common multiple of 16 and 4 is 16. Convert \frac{9}{16} and \frac{3}{4} to fractions with denominator 16.

$$\frac{9}{16}+\frac{12}{16}-3$$

Since \frac{9}{16} and \frac{12}{16} have the same denominator, add them by adding their numerators.

$$\frac{9+12}{16}-3$$

Add 9 and 12 to get 21.

$$\frac{21}{16}-3$$

Convert 3 to fraction \frac{48}{16}.

$$\frac{21}{16}-\frac{48}{16}$$

Since \frac{21}{16} and \frac{48}{16} have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-48}{16}$$

Subtract 48 from 21 to get -27.

$$-\frac{27}{16}$$

Factor

$$-\frac{27}{16} = -1\frac{11}{16} = -1.6875$$