Solve (-3/4+1/6-3/8)*12

$$( - \frac { 3 } { 4 } + \frac { 1 } { 6 } - \frac { 3 } { 8 } ) \times 12$$

Evaluate

$$-\frac{23}{2}=-11.5$$

Solution Steps

Least common multiple of 4 and 6 is 12. Convert -\frac{3}{4} and \frac{1}{6} to fractions with denominator 12.

$$\left(-\frac{9}{12}+\frac{2}{12}-\frac{3}{8}\right)\times 12$$

Since -\frac{9}{12} and \frac{2}{12} have the same denominator, add them by adding their numerators.

$$\left(\frac{-9+2}{12}-\frac{3}{8}\right)\times 12$$

Add -9 and 2 to get -7.

$$\left(-\frac{7}{12}-\frac{3}{8}\right)\times 12$$

Least common multiple of 12 and 8 is 24. Convert -\frac{7}{12} and \frac{3}{8} to fractions with denominator 24.

$$\left(-\frac{14}{24}-\frac{9}{24}\right)\times 12$$

Since -\frac{14}{24} and \frac{9}{24} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-14-9}{24}\times 12$$

Subtract 9 from -14 to get -23.

$$-\frac{23}{24}\times 12$$

Express -\frac{23}{24}\times 12 as a single fraction.

$$\frac{-23\times 12}{24}$$

Multiply -23 and 12 to get -276.

$$\frac{-276}{24}$$

Reduce the fraction \frac{-276}{24} to lowest terms by extracting and canceling out 12.

$$-\frac{23}{2}$$

Factor

$$-\frac{23}{2} = -11\frac{1}{2} = -11.5$$