Solve (-3/2+3/4:6/4)*(-3/4)+frac{1}{5}=

$$( - \frac { 3 } { 2 } + \frac { 3 } { 4 } : \frac { 6 } { 4 } ) \cdot ( - \frac { 3 } { 4 } ) + \frac { 1 } { 5 } =$$

Evaluate

$$\frac{19}{20}=0.95$$

Solution Steps

Divide \frac{3}{4} by \frac{6}{4} by multiplying \frac{3}{4} by the reciprocal of \frac{6}{4}.

$$\left(-\frac{3}{2}+\frac{3\times 4}{4\times 6}\right)\left(-\frac{3}{4}\right)+\frac{1}{5}$$

Cancel out 3\times 4 in both numerator and denominator.

$$\left(-\frac{3}{2}+\frac{1}{2}\right)\left(-\frac{3}{4}\right)+\frac{1}{5}$$

Since -\frac{3}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{-3+1}{2}\left(-\frac{3}{4}\right)+\frac{1}{5}$$

Add -3 and 1 to get -2.

$$\frac{-2}{2}\left(-\frac{3}{4}\right)+\frac{1}{5}$$

Divide -2 by 2 to get -1.

$$-\left(-\frac{3}{4}\right)+\frac{1}{5}$$

Multiply -1 and -\frac{3}{4} to get \frac{3}{4}.

$$\frac{3}{4}+\frac{1}{5}$$

Least common multiple of 4 and 5 is 20. Convert \frac{3}{4} and \frac{1}{5} to fractions with denominator 20.

$$\frac{15}{20}+\frac{4}{20}$$

Since \frac{15}{20} and \frac{4}{20} have the same denominator, add them by adding their numerators.

$$\frac{15+4}{20}$$

Add 15 and 4 to get 19.

$$\frac{19}{20}$$

Factor

$$\frac{19}{2 ^ {2} \cdot 5} = 0.95$$