Solve (-2/9)+(-2/9)*4/9-16/243

$$( - \frac { 2 } { 9 } ) + ( - \frac { 2 } { 9 } ) \times \frac { 4 } { 9 } - \frac { 16 } { 243 }$$

Evaluate

$$-\frac{94}{243}\approx -0.386831276$$

Solution Steps

Multiply -\frac{2}{9} times \frac{4}{9} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{2}{9}+\frac{-2\times 4}{9\times 9}-\frac{16}{243}$$

Do the multiplications in the fraction \frac{-2\times 4}{9\times 9}.

$$-\frac{2}{9}+\frac{-8}{81}-\frac{16}{243}$$

Fraction \frac{-8}{81} can be rewritten as -\frac{8}{81} by extracting the negative sign.

$$-\frac{2}{9}-\frac{8}{81}-\frac{16}{243}$$

Least common multiple of 9 and 81 is 81. Convert -\frac{2}{9} and \frac{8}{81} to fractions with denominator 81.

$$-\frac{18}{81}-\frac{8}{81}-\frac{16}{243}$$

Since -\frac{18}{81} and \frac{8}{81} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-18-8}{81}-\frac{16}{243}$$

Subtract 8 from -18 to get -26.

$$-\frac{26}{81}-\frac{16}{243}$$

Least common multiple of 81 and 243 is 243. Convert -\frac{26}{81} and \frac{16}{243} to fractions with denominator 243.

$$-\frac{78}{243}-\frac{16}{243}$$

Since -\frac{78}{243} and \frac{16}{243} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-78-16}{243}$$

Subtract 16 from -78 to get -94.

$$-\frac{94}{243}$$

Factor

$$-\frac{94}{243} = -0.3868312757201646$$