Solve (-2/3-2/6)+(-2/4-3/9)

$$( - \frac { 2 } { 3 } - \frac { 2 } { 6 } ) + ( - \frac { 2 } { 4 } - \frac { 3 } { 9 } )$$

Evaluate

$$-\frac{11}{6}\approx -1.833333333$$

Solution Steps

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$-\frac{2}{3}-\frac{1}{3}-\frac{2}{4}-\frac{3}{9}$$

Since -\frac{2}{3} and \frac{1}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-2-1}{3}-\frac{2}{4}-\frac{3}{9}$$

Subtract 1 from -2 to get -3.

$$\frac{-3}{3}-\frac{2}{4}-\frac{3}{9}$$

Divide -3 by 3 to get -1.

$$-1-\frac{2}{4}-\frac{3}{9}$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$-1-\frac{1}{2}-\frac{3}{9}$$

Convert -1 to fraction -\frac{2}{2}.

$$-\frac{2}{2}-\frac{1}{2}-\frac{3}{9}$$

Since -\frac{2}{2} and \frac{1}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-2-1}{2}-\frac{3}{9}$$

Subtract 1 from -2 to get -3.

$$-\frac{3}{2}-\frac{3}{9}$$

Reduce the fraction \frac{3}{9} to lowest terms by extracting and canceling out 3.

$$-\frac{3}{2}-\frac{1}{3}$$

Least common multiple of 2 and 3 is 6. Convert -\frac{3}{2} and \frac{1}{3} to fractions with denominator 6.

$$-\frac{9}{6}-\frac{2}{6}$$

Since -\frac{9}{6} and \frac{2}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-9-2}{6}$$

Subtract 2 from -9 to get -11.

$$-\frac{11}{6}$$

Factor

$$-\frac{11}{6} = -1\frac{5}{6} = -1.8333333333333333$$