Solve (-2/3)(+3/4)(-24/5)(-13/7)=

$$( - \frac { 2 } { 3 } ) ( + \frac { 3 } { 4 } ) ( - 2 \frac { 4 } { 5 } ) ( - 1 \frac { 3 } { 7 } ) =$$

Evaluate

$$-2$$

Solution Steps

Multiply -\frac{2}{3} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-2\times 3}{3\times 4}\left(-\frac{2\times 5+4}{5}\right)\left(-\frac{1\times 7+3}{7}\right)$$

Cancel out 3 in both numerator and denominator.

$$\frac{-2}{4}\left(-\frac{2\times 5+4}{5}\right)\left(-\frac{1\times 7+3}{7}\right)$$

Reduce the fraction \frac{-2}{4} to lowest terms by extracting and canceling out 2.

$$-\frac{1}{2}\left(-\frac{2\times 5+4}{5}\right)\left(-\frac{7+3}{7}\right)$$

Multiply 2 and 5 to get 10.

$$-\frac{1}{2}\left(-\frac{10+4}{5}\right)\left(-\frac{7+3}{7}\right)$$

Add 10 and 4 to get 14.

$$-\frac{1}{2}\left(-\frac{14}{5}\right)\left(-\frac{7+3}{7}\right)$$

Multiply -\frac{1}{2} times -\frac{14}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-\left(-14\right)}{2\times 5}\left(-\frac{1\times 7+3}{7}\right)$$

Do the multiplications in the fraction \frac{-\left(-14\right)}{2\times 5}.

$$\frac{14}{10}\left(-\frac{1\times 7+3}{7}\right)$$

Reduce the fraction \frac{14}{10} to lowest terms by extracting and canceling out 2.

$$\frac{7}{5}\left(-\frac{1\times 7+3}{7}\right)$$

Multiply 1 and 7 to get 7.

$$\frac{7}{5}\left(-\frac{7+3}{7}\right)$$

Add 7 and 3 to get 10.

$$\frac{7}{5}\left(-\frac{10}{7}\right)$$

Multiply \frac{7}{5} times -\frac{10}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\left(-10\right)}{5\times 7}$$

Cancel out 7 in both numerator and denominator.

$$\frac{-10}{5}$$

Divide -10 by 5 to get -2.

$$-2$$

Factor

$$-2$$