Solve (-2/3)*(-13/4)*24/5+(-21/3)=

$$( - \frac { 2 } { 3 } ) \times ( - 1 \frac { 3 } { 4 } ) \times 2 \frac { 4 } { 5 } + ( - 2 \frac { 1 } { 3 } ) =$$

Evaluate

$$\frac{14}{15}\approx 0.933333333$$

Solution Steps

Multiply 1 and 4 to get 4.

$$-\frac{2}{3}\left(-\frac{4+3}{4}\right)\times \frac{2\times 5+4}{5}-\frac{2\times 3+1}{3}$$

Add 4 and 3 to get 7.

$$-\frac{2}{3}\left(-\frac{7}{4}\right)\times \frac{2\times 5+4}{5}-\frac{2\times 3+1}{3}$$

Multiply -\frac{2}{3} times -\frac{7}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-2\left(-7\right)}{3\times 4}\times \frac{2\times 5+4}{5}-\frac{2\times 3+1}{3}$$

Do the multiplications in the fraction \frac{-2\left(-7\right)}{3\times 4}.

$$\frac{14}{12}\times \frac{2\times 5+4}{5}-\frac{2\times 3+1}{3}$$

Reduce the fraction \frac{14}{12} to lowest terms by extracting and canceling out 2.

$$\frac{7}{6}\times \frac{2\times 5+4}{5}-\frac{2\times 3+1}{3}$$

Multiply 2 and 5 to get 10.

$$\frac{7}{6}\times \frac{10+4}{5}-\frac{2\times 3+1}{3}$$

Add 10 and 4 to get 14.

$$\frac{7}{6}\times \frac{14}{5}-\frac{2\times 3+1}{3}$$

Multiply \frac{7}{6} times \frac{14}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{7\times 14}{6\times 5}-\frac{2\times 3+1}{3}$$

Do the multiplications in the fraction \frac{7\times 14}{6\times 5}.

$$\frac{98}{30}-\frac{2\times 3+1}{3}$$

Reduce the fraction \frac{98}{30} to lowest terms by extracting and canceling out 2.

$$\frac{49}{15}-\frac{2\times 3+1}{3}$$

Multiply 2 and 3 to get 6.

$$\frac{49}{15}-\frac{6+1}{3}$$

Add 6 and 1 to get 7.

$$\frac{49}{15}-\frac{7}{3}$$

Least common multiple of 15 and 3 is 15. Convert \frac{49}{15} and \frac{7}{3} to fractions with denominator 15.

$$\frac{49}{15}-\frac{35}{15}$$

Since \frac{49}{15} and \frac{35}{15} have the same denominator, subtract them by subtracting their numerators.

$$\frac{49-35}{15}$$

Subtract 35 from 49 to get 14.

$$\frac{14}{15}$$

Factor

$$\frac{2 \cdot 7}{3 \cdot 5} = 0.9333333333333333$$