Solve (-2/3)*(-1/2)^2div(-1/3)=

$$( - \frac { 2 } { 3 } ) \times ( - \frac { 1 } { 2 } ) ^ { 2 } \div ( - \frac { 1 } { 3 } ) =$$

Evaluate

$$\frac{1}{2}=0.5$$

Solution Steps

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{-\frac{2}{3}\times \frac{1}{4}}{-\frac{1}{3}}$$

Multiply -\frac{2}{3} times \frac{1}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\frac{-2}{3\times 4}}{-\frac{1}{3}}$$

Do the multiplications in the fraction \frac{-2}{3\times 4}.

$$\frac{\frac{-2}{12}}{-\frac{1}{3}}$$

Reduce the fraction \frac{-2}{12} to lowest terms by extracting and canceling out 2.

$$\frac{-\frac{1}{6}}{-\frac{1}{3}}$$

Divide -\frac{1}{6} by -\frac{1}{3} by multiplying -\frac{1}{6} by the reciprocal of -\frac{1}{3}.

$$-\frac{1}{6}\left(-3\right)$$

Express -\frac{1}{6}\left(-3\right) as a single fraction.

$$\frac{-\left(-3\right)}{6}$$

Multiply -1 and -3 to get 3.

$$\frac{3}{6}$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2}$$

Factor

$$\frac{1}{2} = 0.5$$