Solve (-2/3+1/2-1/6)^3:(-1/2)^2

$$( - \frac { 2 } { 3 } + \frac { 1 } { 2 } - \frac { 1 } { 6 } ) ^ { 3 } : ( - \frac { 1 } { 2 } ) ^ { 2 }$$

Evaluate

$$-\frac{4}{27}\approx -0.148148148$$

Solution Steps

Add -\frac{2}{3} and \frac{1}{2} to get -\frac{1}{6}.

$$\frac{\left(-\frac{1}{6}-\frac{1}{6}\right)^{3}}{\left(-\frac{1}{2}\right)^{2}}$$

Subtract \frac{1}{6} from -\frac{1}{6} to get -\frac{1}{3}.

$$\frac{\left(-\frac{1}{3}\right)^{3}}{\left(-\frac{1}{2}\right)^{2}}$$

Calculate -\frac{1}{3} to the power of 3 and get -\frac{1}{27}.

$$\frac{-\frac{1}{27}}{\left(-\frac{1}{2}\right)^{2}}$$

Calculate -\frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{-\frac{1}{27}}{\frac{1}{4}}$$

Divide -\frac{1}{27} by \frac{1}{4} by multiplying -\frac{1}{27} by the reciprocal of \frac{1}{4}.

$$-\frac{1}{27}\times 4$$

Multiply -\frac{1}{27} and 4 to get -\frac{4}{27}.

$$-\frac{4}{27}$$

Factor

$$-\frac{4}{27} = -0.14814814814814814$$