Solve (-19/5)^2+2*(-19/5)+3

$$( - \frac { 19 } { 5 } ) ^ { 2 } + 2 \times ( - \frac { 19 } { 5 } ) + 3$$

Evaluate

$$\frac{246}{25}=9.84$$

Solution Steps

Calculate -\frac{19}{5} to the power of 2 and get \frac{361}{25}.

$$\frac{361}{25}+2\left(-\frac{19}{5}\right)+3$$

Express 2\left(-\frac{19}{5}\right) as a single fraction.

$$\frac{361}{25}+\frac{2\left(-19\right)}{5}+3$$

Multiply 2 and -19 to get -38.

$$\frac{361}{25}+\frac{-38}{5}+3$$

Fraction \frac{-38}{5} can be rewritten as -\frac{38}{5} by extracting the negative sign.

$$\frac{361}{25}-\frac{38}{5}+3$$

Least common multiple of 25 and 5 is 25. Convert \frac{361}{25} and \frac{38}{5} to fractions with denominator 25.

$$\frac{361}{25}-\frac{190}{25}+3$$

Since \frac{361}{25} and \frac{190}{25} have the same denominator, subtract them by subtracting their numerators.

$$\frac{361-190}{25}+3$$

Subtract 190 from 361 to get 171.

$$\frac{171}{25}+3$$

Convert 3 to fraction \frac{75}{25}.

$$\frac{171}{25}+\frac{75}{25}$$

Since \frac{171}{25} and \frac{75}{25} have the same denominator, add them by adding their numerators.

$$\frac{171+75}{25}$$

Add 171 and 75 to get 246.

$$\frac{246}{25}$$

Factor

$$\frac{2 \cdot 3 \cdot 41}{5 ^ {2}} = 9\frac{21}{25} = 9.84$$