Solve for m
m = \frac{41}{18} = 2\frac{5}{18} \approx 2.277777778
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-\frac{5}{2}+m=-\frac{2}{9}
Reduce the fraction \frac{15}{6} to lowest terms by extracting and canceling out 3.
m=-\frac{2}{9}+\frac{5}{2}
Add \frac{5}{2} to both sides.
m=-\frac{4}{18}+\frac{45}{18}
Least common multiple of 9 and 2 is 18. Convert -\frac{2}{9} and \frac{5}{2} to fractions with denominator 18.
m=\frac{-4+45}{18}
Since -\frac{4}{18} and \frac{45}{18} have the same denominator, add them by adding their numerators.
m=\frac{41}{18}
Add -4 and 45 to get 41.
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