Solve (-1/8ab^2c)*(-4,25b^2c^0)=

$$( - \frac { 1 } { 8 } a b ^ { 2 } c ) \cdot ( - 4,25 b ^ { 2 } c ^ { 0 } ) =$$

Evaluate

$$\frac{17acb^{4}}{32}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 2 to get 4.

$$-\frac{1}{8}ab^{4}c\left(-4,25\right)c^{0}$$

To multiply powers of the same base, add their exponents. Add 1 and 0 to get 1.

$$-\frac{1}{8}ab^{4}c^{1}\left(-4,25\right)$$

Calculate c to the power of 1 and get c.

$$-\frac{1}{8}ab^{4}c\left(-4,25\right)$$

Multiply -\frac{1}{8} and -4,25 to get \frac{17}{32}.

$$\frac{17}{32}ab^{4}c$$

Differentiate w.r.t. a

$$\frac{17cb^{4}}{32}$$