Solve (-1/6+2/3)quad(1-2/5

$$( - \frac { 1 } { 6 } + \frac { 2 } { 3 } ) \quad ( 1 - \frac { 2 } { 5 }$$

Evaluate

$$\frac{3}{10}=0.3$$

Solution Steps

Least common multiple of 6 and 3 is 6. Convert -\frac{1}{6} and \frac{2}{3} to fractions with denominator 6.

$$\left(-\frac{1}{6}+\frac{4}{6}\right)\left(1-\frac{2}{5}\right)$$

Since -\frac{1}{6} and \frac{4}{6} have the same denominator, add them by adding their numerators.

$$\frac{-1+4}{6}\left(1-\frac{2}{5}\right)$$

Add -1 and 4 to get 3.

$$\frac{3}{6}\left(1-\frac{2}{5}\right)$$

Reduce the fraction \frac{3}{6} to lowest terms by extracting and canceling out 3.

$$\frac{1}{2}\left(1-\frac{2}{5}\right)$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{1}{2}\left(\frac{5}{5}-\frac{2}{5}\right)$$

Since \frac{5}{5} and \frac{2}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1}{2}\times \frac{5-2}{5}$$

Subtract 2 from 5 to get 3.

$$\frac{1}{2}\times \frac{3}{5}$$

Multiply \frac{1}{2} times \frac{3}{5} by multiplying numerator times numerator and denominator times denominator.

$$\frac{1\times 3}{2\times 5}$$

Do the multiplications in the fraction \frac{1\times 3}{2\times 5}.

$$\frac{3}{10}$$

Factor

$$\frac{3}{2 \cdot 5} = 0.3$$