Solve (-1/4-62/3)*96

$$( - \frac { 1 } { 4 } - 6 \frac { 2 } { 3 } ) \cdot 96$$

Evaluate

$$-664$$

Solution Steps

Multiply 6 and 3 to get 18.

$$\left(-\frac{1}{4}-\frac{18+2}{3}\right)\times 96$$

Add 18 and 2 to get 20.

$$\left(-\frac{1}{4}-\frac{20}{3}\right)\times 96$$

Least common multiple of 4 and 3 is 12. Convert -\frac{1}{4} and \frac{20}{3} to fractions with denominator 12.

$$\left(-\frac{3}{12}-\frac{80}{12}\right)\times 96$$

Since -\frac{3}{12} and \frac{80}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-3-80}{12}\times 96$$

Subtract 80 from -3 to get -83.

$$-\frac{83}{12}\times 96$$

Express -\frac{83}{12}\times 96 as a single fraction.

$$\frac{-83\times 96}{12}$$

Multiply -83 and 96 to get -7968.

$$\frac{-7968}{12}$$

Divide -7968 by 12 to get -664.

$$-664$$

Factor

$$-664$$