Solve (-1/4)^3div(-1/4)=(-1/4)

$$( - \frac { 1 } { 4 } ) ^ { 3 } \div ( - \frac { 1 } { 4 } ) = ( - \frac { 1 } { 4 } )$$

Verify

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 1 from 3 to get 2.

$$\left(-\frac{1}{4}\right)^{2}=-\frac{1}{4}$$

Calculate -\frac{1}{4} to the power of 2 and get \frac{1}{16}.

$$\frac{1}{16}=-\frac{1}{4}$$

Least common multiple of 16 and 4 is 16. Convert \frac{1}{16} and -\frac{1}{4} to fractions with denominator 16.

$$\frac{1}{16}=-\frac{4}{16}$$

Compare \frac{1}{16} and -\frac{4}{16}.

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