Solve (-1/3)*(-2/7)*21/4*(-6)

$$( - \frac { 1 } { 3 } ) \cdot ( - \frac { 2 } { 7 } ) \cdot \frac { 21 } { 4 } \cdot ( - 6 )$$

Evaluate

$$-3$$

Solution Steps

Multiply -\frac{1}{3} times -\frac{2}{7} by multiplying numerator times numerator and denominator times denominator.

$$\frac{-\left(-2\right)}{3\times 7}\times \frac{21}{4}\left(-6\right)$$

Do the multiplications in the fraction \frac{-\left(-2\right)}{3\times 7}.

$$\frac{2}{21}\times \frac{21}{4}\left(-6\right)$$

Multiply \frac{2}{21} times \frac{21}{4} by multiplying numerator times numerator and denominator times denominator.

$$\frac{2\times 21}{21\times 4}\left(-6\right)$$

Cancel out 21 in both numerator and denominator.

$$\frac{2}{4}\left(-6\right)$$

Reduce the fraction \frac{2}{4} to lowest terms by extracting and canceling out 2.

$$\frac{1}{2}\left(-6\right)$$

Multiply \frac{1}{2} and -6 to get \frac{-6}{2}.

$$\frac{-6}{2}$$

Divide -6 by 2 to get -3.

$$-3$$

Factor

$$-3$$