Solve (-1/3)^2+(1/3)^0+(1/3)^-3

$$( - \frac { 1 } { 3 } ) ^ { 2 } + ( \frac { 1 } { 3 } ) ^ { 0 } + ( \frac { 1 } { 3 } ) ^ { - 3 }$$

Evaluate

$$\frac{253}{9}\approx 28.111111111$$

Solution Steps

Calculate -\frac{1}{3} to the power of 2 and get \frac{1}{9}.

$$\frac{1}{9}+\left(\frac{1}{3}\right)^{0}+\left(\frac{1}{3}\right)^{-3}$$

Calculate \frac{1}{3} to the power of 0 and get 1.

$$\frac{1}{9}+1+\left(\frac{1}{3}\right)^{-3}$$

Add \frac{1}{9} and 1 to get \frac{10}{9}.

$$\frac{10}{9}+\left(\frac{1}{3}\right)^{-3}$$

Calculate \frac{1}{3} to the power of -3 and get 27.

$$\frac{10}{9}+27$$

Add \frac{10}{9} and 27 to get \frac{253}{9}.

$$\frac{253}{9}$$

Factor

$$\frac{11 \cdot 23}{3 ^ {2}} = 28\frac{1}{9} = 28.11111111111111$$