Solve (-1/3)+(-1/4)+(+2/3)+(+1/2)

$$( - \frac { 1 } { 3 } ) + ( - \frac { 1 } { 4 } ) + ( + \frac { 2 } { 3 } ) + ( + \frac { 1 } { 2 } )$$

Evaluate

$$\frac{7}{12}\approx 0.583333333$$

Solution Steps

Least common multiple of 3 and 4 is 12. Convert -\frac{1}{3} and \frac{1}{4} to fractions with denominator 12.

$$-\frac{4}{12}-\frac{3}{12}+\frac{2}{3}+\frac{1}{2}$$

Since -\frac{4}{12} and \frac{3}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4-3}{12}+\frac{2}{3}+\frac{1}{2}$$

Subtract 3 from -4 to get -7.

$$-\frac{7}{12}+\frac{2}{3}+\frac{1}{2}$$

Least common multiple of 12 and 3 is 12. Convert -\frac{7}{12} and \frac{2}{3} to fractions with denominator 12.

$$-\frac{7}{12}+\frac{8}{12}+\frac{1}{2}$$

Since -\frac{7}{12} and \frac{8}{12} have the same denominator, add them by adding their numerators.

$$\frac{-7+8}{12}+\frac{1}{2}$$

Add -7 and 8 to get 1.

$$\frac{1}{12}+\frac{1}{2}$$

Least common multiple of 12 and 2 is 12. Convert \frac{1}{12} and \frac{1}{2} to fractions with denominator 12.

$$\frac{1}{12}+\frac{6}{12}$$

Since \frac{1}{12} and \frac{6}{12} have the same denominator, add them by adding their numerators.

$$\frac{1+6}{12}$$

Add 1 and 6 to get 7.

$$\frac{7}{12}$$

Factor

$$\frac{7}{2 ^ {2} \cdot 3} = 0.5833333333333334$$