Solve (-1/3+3-1)-(9-9-9)

$$( - \frac { 1 } { 3 } + 3 - 1 ) - ( 9 - 9 - 9 )$$

Evaluate

$$\frac{32}{3}\approx 10.666666667$$

Solution Steps

Convert 3 to fraction \frac{9}{3}.

$$-\frac{1}{3}+\frac{9}{3}-1-\left(9-9-9\right)$$

Since -\frac{1}{3} and \frac{9}{3} have the same denominator, add them by adding their numerators.

$$\frac{-1+9}{3}-1-\left(9-9-9\right)$$

Add -1 and 9 to get 8.

$$\frac{8}{3}-1-\left(9-9-9\right)$$

Convert 1 to fraction \frac{3}{3}.

$$\frac{8}{3}-\frac{3}{3}-\left(9-9-9\right)$$

Since \frac{8}{3} and \frac{3}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8-3}{3}-\left(9-9-9\right)$$

Subtract 3 from 8 to get 5.

$$\frac{5}{3}-\left(9-9-9\right)$$

Subtract 9 from 9 to get 0.

$$\frac{5}{3}-\left(-9\right)$$

The opposite of -9 is 9.

$$\frac{5}{3}+9$$

Convert 9 to fraction \frac{27}{3}.

$$\frac{5}{3}+\frac{27}{3}$$

Since \frac{5}{3} and \frac{27}{3} have the same denominator, add them by adding their numerators.

$$\frac{5+27}{3}$$

Add 5 and 27 to get 32.

$$\frac{32}{3}$$

Factor

$$\frac{2 ^ {5}}{3} = 10\frac{2}{3} = 10.666666666666666$$